On October 27 2008 14:51 micronesia wrote:
Lol what? Serious question nestled in there?
Earth?
Lol what? Serious question nestled in there?
Earth?
you'll know when to take me seriously
Blogs > HeavOnEarth |
Deleted User 3420
24492 Posts
On October 27 2008 14:51 micronesia wrote: Show nested quote + On October 27 2008 14:38 travis wrote: On October 27 2008 14:36 micronesia wrote: On October 27 2008 14:21 HeavOnEarth wrote: thanks! now to um apply that with more examples ahh more hw problems D::: i ran out like this Is it accelerating? Yes, since it's going in a circle. So, Fnet is Ff. why? In order for an object to be accelerating, its velocity must be changing. You can change velocity by accelerating forwards (increasing speed), or accelerating backwards (deceleration; decreasing speed). However, if you go in a circle, your speed is constant, but the direction of the velocity is still changing... so you are accelerating. what if you go in a circle, while twisting on an axis do you go supernova? Lol what? Serious question nestled in there? Earth? you'll know when to take me seriously | ||
HeavOnEarth
United States7087 Posts
On October 28 2008 00:28 Klockan3 wrote: Show nested quote + On October 27 2008 16:05 HeavOnEarth wrote: On October 27 2008 14:38 HeavOnEarth wrote: Likewise, A tired worker pushes with a horizontal force of 400 N on a 100 kg crate initially resting on a thick pile carpet. The coefficients of static and kinetic friction are 0.6 and 0.2, respectively. The acceleration of gravity is 9.81 m/s2 . Find the frictional force exerted by the car- pet on the crate. Answer in units of N. Ok, i know Ff = u*Fn I know F=ma Fg = mg and i can picture the forces 400->>>> horizontally, and 100kg, 9.81 downwards , now the coefficients confuse me =/ I would guess that 0.6 is the static friction and 0.2 is the kinetic friction. Since the crate is initially resting and 400 N is not enough to go above the static friction the answer must be: ??????? Edit: And for what to read to learn the linear algebra needed, read roughly everything in this that is not about matrixes: http://en.wikipedia.org/wiki/Dot_product The dot product is usefull all the time in mechanics since you need to constantly project forces on to surfaces or split them up to get the equations straight etc. Might be a bit abstract but if you plan on doing something that requires college level math then there is no reason not to learn about it now, it is a powerful tool at the same time as the definition of it is really simple. thanks :0 the class didn't even attempt this UT based thing except for like 3 of us, so it's ok. i thought i just failed it horribly, but no one knows whats going on for the most part our teacher is like "sighh i have to teach" | ||
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