On June 09 2009 13:45 For_The_Swarm wrote:
It would be a 1/6th probability to get ZZ if BOTH players went random. However, with one going Z and the other random the probability reduces to 1/3.
Possibilities for RR vs XXX:
ZZ vs XX TT vs XX
ZT vs XX TP vs XX
ZP vs XX PP vs XX
Only 3 possibilities for ZR vs XX:
ZZ vs XX
ZT vs XX
ZP vs XX
It would be a 1/6th probability to get ZZ if BOTH players went random. However, with one going Z and the other random the probability reduces to 1/3.
Possibilities for RR vs XXX:
ZZ vs XX TT vs XX
ZT vs XX TP vs XX
ZP vs XX PP vs XX
Only 3 possibilities for ZR vs XX:
ZZ vs XX
ZT vs XX
ZP vs XX
even if the random generator was completely random do u noe how probability works? u would get 1/3 for one Z and 1/3 for another which makes it 1/9 (= 1/3 * 1/3)